What's the most efficient way to open an Uri?

IP: 85.76.5.49 6 years 10 months ago #14363 by ville

What's the most efficient way to open an Uri? was created by ville

Hi, and thank you for the example!

I have an input stream obtained from a Uri like this:

Code:

final InputStream inputStream = this.application.getContentResolver().openInputStream(uri);

btu doc.Open does not seem to accept Uri nor InputStreams. What's the most efficient way to open an Uri?

IP: 111.196.244.118 6 years 10 months ago #14368 by radaee

Replied by radaee on topic What's the most efficient way to open an Uri?

2 ways you can open from url.
1. download whole PDF file to storage, and then open file from storage.
2. anwser like: www.radaeepdf.com/forum/Android-developm...ages-to-images#14367

IP: 212.149.240.8 6 years 9 months ago #14381 by ville

Replied by ville on topic What's the most efficient way to open an Uri?

Hi,

for future forum travellers: one can use PDFMemStream like this

Code:

PDFMemStream stream = new PDFMemStream(bytes);
int result = doc.OpenStream(stream, null);

Stream to byte buffer is plain ol java, google/stackoverflow that.

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